2x^2=-18+12x

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Solution for 2x^2=-18+12x equation: 



2x^2=-18+12x

We move all terms to the left:

2x^2-(-18+12x)=0

We add all the numbers together, and all the variables

2x^2-(12x-18)=0

We get rid of parentheses

2x^2-12x+18=0

a = 2; b = -12; c = +18;
Δ = b2-4ac
Δ = -122-4·2·18
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{12}{4}=3$

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